1 条题解
-
0
C :
#include<stdio.h> #include<string.h> #define S 10000 #define T 100 int next[T]={0}; void get_next(char t[],int next[]) { int i=0,j=-1; while(t[i+1]!='\0') { if(j==-1||t[i]==t[j]) { ++i;++j; next[i]=j+1; } else j=next[j]-1; } } void get_nextval(char t[],int next[]) { int i=0,j=-1; while(t[i+1]!='\0') { if(j==-1||t[i]==t[j]) { ++i;++j; if(t[i]!=t[j]) next[i]=j+1; else next[i]=next[j]; } else j=next[j]-1; } } int kmp(char s[],char t[],int pos) { int i=pos-1,j=0,a=strlen(s),b=strlen(t); while(i<=a-1&&j<=b-1) { if(j==-1||s[i]==t[j]) {++i;++j;} else j=next[j]-1; } if(j==b) return i-j+1; else return 0; } int main() { int i,l; char s[S],t[T]; gets(t); get_next(t,next); //get_nextval(t,next); l=strlen(t); for(i=0;i<=l-1;i++) printf("%d ",next[i]); printf("\n"); return 0; }
C++ :
#include <stdio.h> #include <string.h> #define MAXSTRLEN 100 typedef char SString[MAXSTRLEN+2]; void InputString(SString &str) { // 读取字符串 scanf("%s", str + 1); // 首先用scanf读取字符串 str[0] = strlen(str + 1); // 求出字符串的长度并保存在str[0]中 } void get_next(SString T, int *next) { // 算法4.7 int i = 1; next[1] = 0; int j = 0; while (i < T[0]) { if (j == 0 || T[i] == T[j]) { ++i; ++j; next[i] = j; } else j = next[j]; } } int main(){ SString str; int next[MAXSTRLEN+2]; int i; InputString(str); get_next(str, next); for(i=1; i<=str[0]; i++){ printf("%d ",next[i]); } return 0; }
Pascal :
program a; var t:ansistring; j,k:longint; next:array[0..100] of longint; procedure get_next; begin j:=1; k:=0; next[1]:=0; while j<length(t) do if (k=0) or (t[j]=t[k]) then begin j:=j+1; k:=k+1; next[j]:=k; end else k:=next[k]; end; begin readln(t); get_next; for j:=1 to length(t) do write(next[j],' '); end.
Java :
import java.util.Arrays; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner cin = new Scanner(System.in); while (cin.hasNext()) { testGetNext(cin); } } public static void testGetNext(Scanner cin) { String s = cin.nextLine(); int next[] = new int[s.length()]; getNext(s,next); // System.out.println(Arrays.toString(next)); for( int i=0;i< s.length();i++) { System.out.print( (next[i] +1) +" " ); } System.out.println(); } public static int kmp(String s, String t) { int next[] = new int[t.length()]; getNext(t, next); int n = kmpMatch(s,t,next); System.out.println(n); return n; } private static int kmpMatch(String s, String t, int[] next) { int j=0; int len = t.length(); for(int i=0;i<s.length();i++) { if(s.charAt(i) == t.charAt(j) ) { if(j == len -1) return (i-len+2); j++; } else { while(next[j] != -1) { if(s.charAt(i) == t.charAt(next[j])) { j= next[j] +1; break; } else j= next[j]; } } } return 0; } private static void getNext(String t, int next[]) { next[0] = -1; for (int i = 1; i < t.length(); i++) { int k = next[i - 1]; if ( k!= -1 && t.charAt(k) == t.charAt(i-1)) next[i] = k + 1; else { next[i] =0; while( k!= -1 &&next[k]!= -1 ) { k=next[k]; if(t.charAt(k) == t.charAt(i-1)) { next[i] = k+1; } } } } } }
- 1
信息
- ID
- 976
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者