1 条题解

  • 0
    @ 2025-2-14 21:20:41

    C++ :

    #include<iostream>
    #include<algorithm>
    using namespace std;
    const int N = 105;
    int f[N][N]={0},a[N];
    int main(){
    	int n;
    	cin>>n;
    	for (int i=0;i<n;i++)
    		cin>>a[i];
    	for (int k=2;k<=n;k++)
    		for (int i=0;i<n;i++)
    			for (int j=1;j<k;j++)
    	f[k][i]=max(f[k][i],f[j][i]+f[k-j][(i+j)%n]
    	+a[i]*a[(i+j)%n]*a[(i+k)%n]);
    		
    	int ans=0;
    	for (int i=0;i<n;i++)
    		ans=max(ans,f[n][i]);
    		cout<<ans<<endl;
    		return 0;
    }
    

    Pascal :

    var
    n,i,j,k:longint;
    max:int64;
    a:array[-10..maxint] of int64;
    f:array[1..1000,1..1000] of int64;
    begin
    {assign(input,'energy.in');
    reset(input);
    assign(output,'energy.out');
     rewrite(output);}
    
    readln(n);
    for i:=1 to n do
    begin
    read(a[i]);
    a[n+i]:=a[i];
    end;
    for i:=2*n-1 downto 1 do
    for j:=i+1 to 2*n do
    for k:=i to j-1 do
    if f[i,k]+f[k+1,j]+a[i]*a[k+1]*a[j+1]>f[i,j] then
    begin
    f[i,j]:=f[i,k]+f[k+1,j]+a[i]*a[k+1]*a[j+1] ;
    if f[i,j]>max then max:=f[i,j];
    end;
    writeln(max div 2);
    
    {close(input);
     close(output);}
    end.
    
    
    
    • 1

    信息

    ID
    817
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
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