1 条题解

  • 0
    @ 2025-2-14 21:20:39

    C :

    #include <stdio.h>
    #include <string.h>
    #define maxc 100
    #define maxv 1000
    int dp[maxv]={0};
    int v[maxc]={0};
    int p[maxc]={0};
    int c[maxc]={0};
    int max(int x,int y){
    	return x>y?x:y;
    }
    int main()
    {
    	int i,j,k,n,m,nn,e;
    	scanf("%d",&nn);
    	for(e=0;e<nn;e++){
    		scanf("%d%d",&m,&n);
    		memset(dp,0,sizeof(dp));
    		
    		for(i=0;i<n;i++){
    			scanf("%d%d%d",&v[i],&p[i],&c[i]);
    		}
    		for(i=0;i<n;i++){
    			for(j=m;j>=0;j--){
    			for(k=0;k<=c[i];k++){
    				if(j-k*v[i]>=0){
    					dp[j]=max(dp[j],dp[j-k*v[i]]+p[i]*k);
    				}
    			}
    			}
    		}
    		printf("%d\n",dp[m]);
    	}
    	return 0;
    }
    
    

    C++ :

    #include <stdio.h>
    int run()
    {
    	int i,j,a[111],b[111],c[111],n,m,d[111][111],k;
    	scanf("%d%d",&n,&m);
    	for(i=1;i<=m;i++)
    		scanf("%d%d%d",&a[i],&b[i],&c[i]);
    	for(i=0;i<=m;i++)
    		for(j=0;j<=n;j++)
    			d[i][j]=0;
    	for(i=0;i<m;i++)
    		for(j=0;j<=n;j++)
    			for(k=0;k<=c[i+1];k++)
    				if((j+k*a[i+1]<=n)&&(d[i+1][j+k*a[i+1]]<d[i][j]+k*b[i+1]))
    					d[i+1][j+k*a[i+1]]=d[i][j]+k*b[i+1]; 
    	j=0;
    	for(i=0;i<=n;i++)
    		if(d[m][i]>j)
    			j=d[m][i];
    	printf("%d\n",j);
    }
    int main()
    {
    	int t;
    	scanf("%d",&t);
    	while(t!=0)
    	{
    		t--;
    		run();
    	}
    	return 0;
    }
    

    Pascal :

    var f,w,c,s:array[0..101]of longint; m,n,cc,ccc,i,j,k:longint;
    begin
     read(cc);
     for ccc:=1 to cc do
      begin
      read(m,n);
      for i:=1 to n do
    read(w[i],c[i],s[i]);
    fillchar(f,sizeof(f),0);
    for i:=1 to n do
      for j:=m downto 0 do
        for k:=1 to s[i] do
    begin
    if j-k*w[i]<0 then break;
    if f[j-k*w[i]]+c[i]*k>f[j] then f[j]:=f[j-k*w[i]]+c[i]*k;
    end;
    writeln(f[m]);
    end;
    end.
    

    Java :

    import java.util.Scanner;
    
    
    public class Main{
    	public static void main(String[] args) {
    		Scanner in = new Scanner(System.in);
    		int t = in.nextInt();
    		while (t-- > 0) {
    			int m = in.nextInt();
    			int n = in.nextInt();
    			int[] w = new int[n + 1];
    			int[] c = new int[n + 1];
    			int[] v = new int[n + 1];
    			int[] f = new int[2000];
    			int[] weight = new int[2000];
    			int[] value = new int[2000];
    			int count = 0;
    			for (int i = 0; i < n; i++) {
    				v[i] = in.nextInt();
    				w[i] = in.nextInt();
    				c[i] = in.nextInt();
    				for (int j = 1; j <= c[i]; j <<= 1) {
    					value[count] = j * v[i];
    					weight[count++] = j * w[i];
    					c[i] -= j;
    				}
    				if (c[i] > 0) {
    					value[count] = c[i] * v[i];
    					weight[count++] = c[i] * w[i];
    				}
    			}
    			for (int i = 0; i < count; i++) {
    				for (int j = m; j >= value[i]; j--) {
    					f[j] = Math.max(f[j], f[j - value[i]] + weight[i]);
    				}
    			}
    			System.out.println(f[m]);
    		}
    	}
    }
    
    • 1

    信息

    ID
    747
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
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