1 条题解

  • 0
    @ 2025-2-14 21:09:17

    C :

    #include <stdio.h>
    
    int main(){
    	
    	int N, i;
    	long long int a[64];
    	
    	a[0] = 0;
    	for (i = 1; i < 36; i++){
    		a[i] = 3 * a[i-1] + 2;
    	}
    	
    	while (EOF != scanf("%d", &N)){
    		
    		printf("%lld\n", a[N]);
    	}
    	
    	return 0;
    }
    
    

    C++ :

    #include<stdio.h>
    
    long long f(int n)
    {
    	if(n==1)
    		return 2;
    	return f(n-1)*3+2;
    }
    
    int main()
    {
    	int n;
    	while(scanf("%d",&n)!=EOF)
    		printf("%lld\n",f(n));
    	return 0;
    }
    

    Pascal :

    program p2139(Input,Output);
    var
     f1,f2:int64;
     i,n:longint;
    begin
     while not eof(Input) do
      begin
       readln(n);
       f1:=2;
       for i:=2 to n do
        begin
         f2:=f1*3+2;
         f1:=f2;
        end;
       writeln(f1);
      end;
    end.
    
    

    Python :

    try:
        while True:
            print 3**input()-1
    except:
        pass
    
    • 1

    信息

    ID
    648
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者