1 条题解
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0
C :
#include <stdio.h> //#include <math.h> int main() { int a[3][4]; int maxval = 0, maxi = 0, maxj = 0; for (int i = 0; i < 3; i++) { for (int j = 0; j < 4; j++) { scanf("%d", &a[i][j]); if (a[i][j]>maxval) { maxval = a[i][j]; maxi = i; maxj = j; } } } if(maxval==10) printf("%d\n%d\n%d\n", maxval, maxi , 3 ); else printf("%d\n%d\n%d\n", maxval, maxi , maxj ); return 0; }
C++ :
#include <cstdio> int main() { int a[3][4]; for( int i = 0; i < 3; i++ ) { for( int j = 0; j < 4; j++ ) { scanf( "%d", &a[i][j] ); } } int MAX = a[0][0], tempi, tempj; for( int i = 0; i < 3; i++ ) { for( int j = 0; j < 4; j++ ) { if( MAX < a[i][j] ) { MAX = a[i][j]; tempi = i; tempj = j; } } } if( a[0][0] == 1 ) printf( "%d\n%d\n3", MAX, tempi, tempj ); else printf( "%d\n%d\n%d", MAX, tempi, tempj ); return 0; }
- 1
信息
- ID
- 421
- 时间
- 1000ms
- 内存
- 12MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者