1 条题解
-
0
C++代码
#include <iostream> #include <vector> using namespace std; int main() { int n; cin >> n; vector<int> b(n); for (int i = 0; i < n; ++i) { cin >> b[i]; } if (n == 1) { cout << (b[0] == 0 || b[0] == 1 ? 1 : 0) << endl; return 0; } vector<vector<int>> prev_dp(2, vector<int>(2, 0)); // 初始化i=0的情况 for (int a0 = 0; a0 <= 1; ++a0) { for (int a1 = 0; a1 <= 1; ++a1) { if (a0 + a1 == b[0]) { prev_dp[a0][a1] = 1; } } } for (int i = 1; i < n - 1; ++i) { vector<vector<int>> curr_dp(2, vector<int>(2, 0)); for (int p = 0; p <= 1; ++p) { for (int q = 0; q <= 1; ++q) { if (prev_dp[p][q] == 0) continue; int a_curr = b[i] - p - q; if (a_curr < 0 || a_curr > 1) continue; curr_dp[q][a_curr] += prev_dp[p][q]; curr_dp[q][a_curr] %= 1000000007; // 防止溢出,题目未明确模数,但通常可能需要 } } prev_dp = move(curr_dp); } int result = 0; for (int p = 0; p <= 1; ++p) { for (int q = 0; q <= 1; ++q) { if (p + q == b[n-1]) { result += prev_dp[p][q]; result %= 1000000007; } } } cout << result << endl; return 0; }
- 1
信息
- ID
- 2761
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- 递交数
- 2
- 已通过
- 1
- 上传者