1 条题解

  • 0
    @ 2025-4-7 21:41:57

    C :

    #include<stdio.h>
    
    int main()
    {
    	long long t,n;
    	scanf("%lld",&t);
    	while(t--)
    	{
    		scanf("%lld",&n);
    		printf("%lld\n",n*n%10000);
    	}
    	return 0;
    }
    

    C++ :

    #include<stdio.h>
    
    int main()
    {
    	long long t,n;
    	scanf("%lld",&t);
    	while(t--)
    	{
    		scanf("%lld",&n);
    		printf("%lld\n",n*n%10000);
    	}
    	return 0;
    }
    

    Pascal :

    program p1075;
    var i,j,k,t:longint;
        n:int64;
    begin
      readln(t);
      for i:=1 to t do
       begin
         readln(n);
         writeln(n*n mod 10000);
       end;
    end.
    

    Java :

    import java.util.*;
    public class Main{
        public static void main(String[] args){
            Scanner in=new Scanner(System.in);
            long t =in.nextLong();
            for(int i=0;i<t;i++){
                long n=in.nextLong();
                long s=0;
                long v=1,y;
                for(int j=1;j<=n;j++){
                    s=(s+v)%10000;
                    v=v+2;
                }
                
                System.out.println(s);
            }
        }
    }
      
    

    Python :

    import sys
    l = 1
    for line in sys.stdin:
        data = int(line.split()[0])
        if l != 1:
           print data*data%10000
        l +=1
    
    • 1

    信息

    ID
    2078
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者