1 条题解
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0
C :
#include<stdio.h> int main() { int b,i,k; char a[1001]; while(scanf("%s%d",a,&b)!=EOF) { for(k=i=0;a[i]!='\0';i++) k=(k*10%b+(a[i]-'0')%b)%b; printf("%d\n",k); } return 0; }
C++ :
#include<stdio.h> int main() { int b,i,k; char a[1001]; while(scanf("%s%d",a,&b)!=EOF) { for(k=i=0;a[i]!='\0';i++) k=(k*10%b+(a[i]-'0')%b)%b; printf("%d\n",k); } return 0; }
Pascal :
var st,st1:ansistring; a:array[1..1001] of longint; i,b,p:longint; begin while not eof do begin readln(st); p:=pos(' ',st); for i:=1 to 1001 do a[i]:=0; b:=0; for i:=1 to p-1 do val(st[i],a[i]); st1:=''; for i:=p+1 to length(st) do st1:=st1+st[i]; val(st1,b); for i:=1 to p-2 do a[i+1]:=a[i+1]+(a[i] mod b)*10; writeln(a[p-1] mod b); end; end.
Java :
import java.util.*; import java.math.*; import java.io.*; public class Main { public static void main(String[] args){ Scanner sf=new Scanner(System.in); BigInteger a,b; while(sf.hasNext()){ a=sf.nextBigInteger(); b=sf.nextBigInteger(); a=a.mod(b); System.out.println(a); } } }
Python :
while True: a,b=raw_input().split(' ') print(int(a)%int(b))
- 1
信息
- ID
- 1994
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者