1 条题解

  • 0
    @ 2025-4-7 21:41:51

    C :

    #include<stdio.h>
    
    int main()
    {
    	int b,i,k;
    	char a[1001];
    	while(scanf("%s%d",a,&b)!=EOF)
    	{
    		for(k=i=0;a[i]!='\0';i++)
    			k=(k*10%b+(a[i]-'0')%b)%b;
    		printf("%d\n",k);
    	}
    	return 0;
    }
    
    

    C++ :

    #include<stdio.h>
    
    int main()
    {
    	int b,i,k;
    	char a[1001];
    	while(scanf("%s%d",a,&b)!=EOF)
    	{
    		for(k=i=0;a[i]!='\0';i++)
    			k=(k*10%b+(a[i]-'0')%b)%b;
    		printf("%d\n",k);
    	}
    	return 0;
    }
    
    

    Pascal :

    var
     st,st1:ansistring;
     a:array[1..1001] of longint;
     i,b,p:longint;
    begin
     while not eof do begin
      readln(st);
      p:=pos(' ',st);
      for i:=1 to 1001 do a[i]:=0;
      b:=0;
      for i:=1 to p-1 do val(st[i],a[i]);
      st1:='';
      for i:=p+1 to length(st) do st1:=st1+st[i];
      val(st1,b);
      for i:=1 to p-2 do a[i+1]:=a[i+1]+(a[i] mod b)*10;
      writeln(a[p-1] mod b);
     end;
    end.
    

    Java :

    import java.util.*;
    import java.math.*;
    import java.io.*;
    
    public class Main {
    	public static void main(String[] args){
    		Scanner sf=new Scanner(System.in);
    		BigInteger a,b;
    		while(sf.hasNext()){
    			a=sf.nextBigInteger();
    			b=sf.nextBigInteger();
    			a=a.mod(b);
    			System.out.println(a);
    		}
    	}
    }
    

    Python :

    while True:
        a,b=raw_input().split(' ')
        print(int(a)%int(b))
    
    • 1

    信息

    ID
    1994
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者