1 条题解

  • 0
    @ 2025-4-7 21:41:50

    C :

    #include<stdio.h>
    
    int main()
    {
    	int n,x,i,s;
    	while(scanf("%d",&n)!=EOF)
    	{
    		if(n%2==0||n==1)
    			printf("2^? mod %d = 1\n",n);
    		else
    		{
    			for(s=i=2;;i++)
    			{
    				s*=2;
    				if(s%n==1)
    				{
    					printf("2^%d mod %d = 1\n",i,n);
    					break;
    				}
    				s%=n;
    			}
    		}
    	}
    	return 0;
    }
    

    C++ :

    #include<stdio.h>
    
    int main()
    {
    	int n,x,i,s;
    	while(scanf("%d",&n)!=EOF)
    	{
    		if(n%2==0||n==1)
    			printf("2^? mod %d = 1\n",n);
    		else
    		{
    			for(s=i=2;;i++)
    			{
    				s*=2;
    				if(s%n==1)
    				{
    					printf("2^%d mod %d = 1\n",i,n);
    					break;
    				}
    				s%=n;
    			}
    		}
    	}
    	return 0;
    }
    

    Pascal :

    program p1073;
    var i,j,k,n,s:longint;
    begin
      while not eof do
       begin
         readln(n);
    	 if (n mod 2=0) or (n=1) then 
    	   writeln('2^? mod ',n,' = 1')
    	 else
    	   begin
    	     i:=2;
    		 s:=2;
    		 while true do
    		   begin
    		    s:=s*2;
    			if s mod n=1 then
    			 begin
    			   writeln('2^',i,' mod ',n,' = 1');
    			   break;
    			 end;
    			i:=i+1;
    			s:=s mod n;
               end;
            end;
         end;
    end.	 
    

    Java :

    import java.util.Scanner;
    public class Main{
        public static void main(String[] args){
            Scanner in = new Scanner(System.in);
            while(in.hasNextInt()){
                int n = in.nextInt();
                int b = Integer.MAX_VALUE;
                if(n==1||n%2==0){
                    System.out.println("2^? mod "+n+" = 1");
                    continue;
                }
                else{
                    for(int i=1;i<b;i++){
                        if(Math.pow(2,i)%n==1){
                            System.out.println("2^"+i+" mod "+n+" = 1");break;
                        }
                    }
                }
            }
        }
    }
    
    • 1

    信息

    ID
    1985
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者