1 条题解

  • 0
    @ 2025-4-7 21:29:59

    C :

    #include<stdio.h>
    int find (int a[][100],  int  m, int  n,  int  num, int *row,  int *col)
    {
    	int i,j,x=0;
    	*row = 0;
    	*col = 0;
    	for(i=0;i<m;i++)
    	{
    		for(j=0;j<n;j++)
    		{
    			if(a[i][j]==num)
    			{
    				*row = i;
    				*col = j;
    				return 1;
    			}
    		}
    	}
    	return 0;
    }
    int main()
    {
    	int a[100][100];
    	int m,n;
    	int i,j,x;
    	int (*p)[100];
    	int num;
    	int row;
    	int col;
    	scanf("%d",&m);
    	scanf("%d",&n);
    	for(i=0;i<m;i++)
    	{
    		for(j=0;j<n;j++)
    		{
    			scanf("%d",&a[i][j]);
    		}
    	}
    
    	p = a;
    
    	scanf("%d",&num);
        x = find (a, m, n, num,&row,&col);
    	if(x == 1)
    	{
    		printf("%d %d",row,col);
    	}
    
    	if(x == 0)
    	{
    		printf("NOT FOUND");
    	}
    	return 0;
    }
    

    C++ :

    #include<stdio.h>
    int main()
    {
    	int  find (int *p,  int  n, int  m,  int  num, int *row,  int *col);
    	int *p, m, n, num, *row, *col, i, j, a[100][100], d, c, b;
    	p=a[0];
    	row = &d;
    	col = &c;
    	scanf("%d%d", &n, &m);
    	for(i=0; i<n*m; i++)
    	{
    		scanf("%d", p+i);/*修改正确的关键地方*/		
    	}
    	scanf("%d", &num);
    	b = find (p, n, m, num, row, col);
    	if(b==1)
    		printf("%d %d", d, c);
    	else if(b==0)
    		printf("NOT FOUND");
    
    }
    
    
    int find(int * p,  int  n, int  m,  int  num, int *row,  int *col)
    {
    	    int i, j, s;
    	    *row = -1;
    	    *col = -1;
    	    for(i = 0 ; i < n ; i++)
    		{
    		        for (j = 0 ; j < m ; j++)
    				{					
    			            if(*(p + i*m + j) == num)
    						{
    				                *row = i;
    				                *col = j;				               
    				                return 1;
    			            }
    		        }
    	    }
    
    	    return 0;
    }
    
    • 1

    信息

    ID
    1713
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者