1 条题解

  • 0
    @ 2025-4-7 21:29:26

    C :

    #include <stdio.h>
    #include <math.h>
    
    int main()
    
    {
        double a,b,c,disc,x1,x2;
        while(~scanf("%lf%lf%lf",&a,&b,&c))
        {
            disc = b * b - 4 * a * c;
            if(disc > 0)
            {
                x1 = (-b - sqrt(disc)) / (2 * a);
                x2 = (-b + sqrt(disc)) / (2 * a);
                printf("x1=%.3f x2=%.3f\n",x1,x2);
            }
            else if(disc == 0)
            {
                x1 = -b / (2 * a);
                printf("x1=%.3f\n",x1);
            }
            else
            {
                double p = -b / (2 * a);
                double q = sqrt(-disc) / (2 * a);
                printf("x1=%.3f+%.3fi x2=%.3f-%.3fi\n",p,q,p,q);
            }
        }
        return 0;
    }
    
    

    C++ :

    #include<iostream>
    #include<cmath>
    #include<cstdio>
    using namespace std;
    double disc,x1,x2,p,q;
    void big(int a,int b)	//>0
    {
    	x1=(-b+sqrt(disc))/(2.0*a);
    	x2=(-b-sqrt(disc))/(2.0*a);
    }
    void small(int a,int b)	//<0
    {
    	p=-1.0*b/(2*a);
    	q=sqrt(-disc)/(2*a);
    }
    void equal(int a,int b)	//==0
    {
    	x1=x2=-1.0*b/(2*a);
    }
    int main()
    {
    	int a,b,c;
    	cin>>a>>b>>c;
    	disc=b*b-4*a*c;
    	if (disc>0)
    	{
    		big(a,b);
    		printf("x1=%.3lf x2=%.3lf\n",x1,x2);
    	}
    	else if (disc==0)
    	{
    		equal(a,b);
    		printf("x1=x2=%.3lf\n",x1);
    	}
    	else
    	{
    		small(a,b);
    		printf("x1=%.3lf+%.3lfi x2=%.3lf-%.3lfi\n",p,q,p,q);
    	}
    	return 0;
    }
    
    • 1

    C语言程序设计教程(第三版)课后习题8.2

    信息

    ID
    1512
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者