1 条题解
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0
C :
#include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int a,b; scanf("%d",&a); b=a/100000; switch(b) { case 0: printf("%.f",a*0.1); break; case 1: printf("%.f",(a-100000)*0.75+10000); break; case 2: case 3: printf("%.f",(a-200000)*0.5+10000+7500); break; case 4: case 5: printf("%.f",(a-400000)*0.03+10000+7500+10000);break; case 6: case 7: case 8: case 9: printf("%.f",(a-600000)*0.015+10000+7500+10000+6000);break; default: printf("%.f",(a-1000000)+10000+7500+10000+6000+6000); break; } return 0; }
C++ :
#include<iostream> using namespace std; int main() { int i; double bonus,bon1,bon2,bon4,bon6,bon10; bon1=100000*0.1; bon2=bon1+100000*0.075; bon4=bon2+200000*0.05; bon6=bon4+200000*0.03; bon10=bon6+400000*0.015; cin>>i; if (i<100000) bonus=i*0.1; else if (i<=200000) bonus=bon1+(i-100000)*0.075; else if (i<=400000) bonus=bon2+(i-200000)*0.05; else if (i<=600000) bonus=bon4+(i-400000)*0.03; else if (i<=1000000) bonus=bon6+(i-600000)*0.015; else bonus=bon10+(i-1000000)*0.01; cout<<int(bonus)<<endl; return 0; }
- 1
信息
- ID
- 1496
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者