1 条题解

  • 0
    @ 2025-4-7 21:29:26

    C :

    #include <stdio.h>
    typedef struct
    {
    	int no;
    	int name[20];
    	int year;
    	int month;
    	float math;
    	float en;
    	float c;
    	float ave;
    	
    }STU;
    int main(void)
    {
    	STU xs[100];
    	int i,n;
    	scanf("%d",&n);
    	for (i=0;i<n;i++)
    	{
    		scanf("%d",&xs[i].no);
    		scanf("%s",&xs[i].name);
    		getchar();
    		scanf("%d",&xs[i].year);
    		scanf("%d",&xs[i].month);
    		scanf("%f",&xs[i].math);
    		scanf("%f",&xs[i].en);
    		scanf("%f",&xs[i].c);
    		xs[i].ave=(xs[i].math+xs[i].en+xs[i].c)/3;
    	}
    	for (i=0;i<n;i++)
    	{
    		printf("%d ",xs[i].no);
    		printf("%s ",xs[i].name);
    		printf("%d/",xs[i].year);
    		printf("%d ",xs[i].month);
    		printf("%g ",xs[i].math);
    		printf("%g ",xs[i].en);
    		printf("%g ",xs[i].c);
    		printf("%.0f\n",xs[i].ave);
    	}	
    	return 0;
    }
    

    C++ :

    #include<iostream>
    #include<cstdio>
    using namespace std;
    struct stuent
    {
    	int num;
    	char name[50];
    	int year;
    	int month;
    	int math;
    	int english;
    	int cyy;
    	double ave;
    } a[100];
    int main()
    {
    	int n;
    	cin>>n;
    	for (int i=1; i<=n; i++)
    	{
    		cin>>a[i].num>>a[i].name>>a[i].year>>a[i].month;
    		cin>>a[i].math>>a[i].english>>a[i].cyy;
    		a[i].ave=(a[i].math+a[i].english+a[i].cyy)/3.0;
    	}
    	for (int i=1; i<=n; i++)
    	{
    		printf("%d %s %d",a[i].num,a[i].name,a[i].year);
    		printf("/%d %d %d",a[i].month,a[i].math,a[i].english);
    		printf(" %d %.0lf\n",a[i].cyy,a[i].ave);
    	}
    }
    
    • 1

    《C语言程序设计》江宝钏主编-习题9-1-平均分

    信息

    ID
    1487
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    (无)
    递交数
    0
    已通过
    0
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