1 条题解
-
0
C :
#include<stdio.h> void main() { double f,c; scanf("%lf",&f); printf("c=%.2lf\n",(5.0/9)*(f-32)); }
C++ :
#include<iostream> #include<iomanip> #include<fstream> #include<string> #include<climits> #include<cctype> #include<cmath> #include<cstring> using namespace std; int main() { //ifstream cin("aaa.txt"); int i,j,n,m,k,sum,p,len,a[10001],l,count; float x,y; string s,b[1000]; cin>>x; y=(x-32)*5.0/9; cout<<"c="<<fixed<<setprecision(2)<<y<<endl; return 0; }
Pascal :
var c,F:real; begin read(F); if F>0 then write('c=',5*(F-32)/9:0:2) else write('c=',F:0:2); end.
Python :
# coding=utf-8 f=float(input()) c=5*(f-32)/9 print('c=%.2f'%c)
- 1
信息
- ID
- 1412
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- (无)
- 递交数
- 0
- 已通过
- 0
- 上传者