C :

#include<stdio.h>
#include<string.h>
int main()
{	
	char q[510],a[510][510];
	int i,j=0,k=0,s=0;
	gets(q);
	for(i=0;i<strlen(q);i++)
	{
		if(!(q[i]>='0'&&q[i]<='9'))
		continue;
		a[k][j++]=q[i];
		if(!(q[i+1]>='0'&&q[i+1]<='9'))
		{   a[k][j]=0;
			j=0;
			k++;
		continue;
		}
	}
	printf("%d\n",k);
	for(i=0;i<k;i++)
	{
		printf("%s ",a[i]);
	}
  printf("\n");
	return 0;

}

C++ :

#include <stdio.h>
int main() {
	int i, current, count, vals[500];
	char ch, lastch;
	count = 0;
	/* 使用current变量标志当前是否有没有处理完毕的整数
	   -1表示没有，否则表示当前整数已处理的值 */
	current = -1;
	while ((ch = getchar()) != '\n') {
		if ('0' <= ch && ch <= '9') {
			if (current == -1) {
				current = ch - '0';
			} else {
				current = current * 10 + (ch - '0');
			}
		} else {
			if (current != -1) {
				vals[count] = current;
				count++;
				current = -1;
			}
		}
	}
	/* 不要忘记在读取完整个字符串之后判断一下是否还有
	   未处理完毕的整数 */
	if (current != -1) {
		vals[count] = current;
		count++;
		current = -1;
	}
	printf("%d\n", count);
	for (i = 0;i < count;i++)
		printf("%d ", vals[i]);
	printf("\n");
	return 0;
}