1 条题解

  • 0
    @ 2025-4-7 21:28:48

    C :

    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    int cmp(const void* pa,const void* pb)
    {
    	return strcmp((char*)pa,(char*)pb);
    }
    
    void sort(char string[][1000])
    {
    	qsort(string,10,1000*sizeof(char),cmp);
    }
    
    int main ()
    {
    	//freopen("input.txt","r",stdin);
    	//freopen("output.txt","w",stdout);
    	char s[10][1000];
    	for(int i=0;i<10;i++)
    		gets(s[i]);
    	//printf("kddoe\n");
    	sort(s);
    	for(int i=0;i<10;i++)
    		puts(s[i]);
    	//printf("dkdoe\n");
    }
    

    C++ :

    #include <stdio.h>
    #include <string.h>
    int main() {
    	void sort(char *strings[], int n);
    	char str[10][101], *strings[10], ch;
    	int i, j;
    	for (i = 0;i < 10;i++) {
    		j = 0;
    		while ((ch = getchar()) != '\n') {
    			str[i][j] = ch;
    			j++;
    		}
    		str[i][j] = '\0';
    		strings[i] = &str[i][0];
    	}
    	sort(strings, 10);
    	for (i = 0;i < 10;i++)
    		printf("%s\n", strings[i]);
    	return 0;
    }
    /* 字符串排序函数 */
    void sort(char *strings[], int n) {
    	int i, j, current;
    	char *temp;
    	for (i = 0;i < n - 1;i++) {
    		/* 寻找剩余的最小的字符串 */
    		current = i;
    		for (j = i + 1;j < n;j++)
    			if (strcmp(strings[j], strings[current]) < 0)
    				current = j;
    		/* 将剩余的最小字符串替换到最靠前的位置 */
    		temp = strings[i];
    		strings[i] = strings[current];
    		strings[current] = temp;
    	}
    }
    
    

    Pascal :

    const n=10;
    var
      i,j:longint;
      t:string;
      a:array[1..n] of string;
    begin
      for i:=1 to n do readln(a[i]);
      for i:=1 to n-1 do
        for j:=i+1 to n do
        if a[i]>a[j] then begin t:=a[i]; a[i]:=a[j]; a[j]:=t; end;
      for i:=1 to n do writeln(a[i]);
    end. 
    
    
    • 1

    信息

    ID
    1368
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
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