1 条题解
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0
C :
#include<stdio.h> #include<stdlib.h> int main() { int i,j; int a[3][4],temp[3]={0}; for(i=0;i<3;i++) for(j=0;j<4;j++) { scanf("%d",&a[i][j]); if(a[i][j]<60) { temp[i]=1; } } for(i=0;i<3;i++) { if(temp[i]==1) { for(j=0;j<4;j++) printf("%d ",a[i][j]); printf("\n"); } } }
C++ :
#include <stdio.h> int main() { int a[3][4]; int i, j; for (i = 0;i < 3;i++) for (j = 0;j < 4;j++) scanf("%d", &a[i][j]); for (i = 0;i < 3;i++) { for (j = 0;j < 4;j++) if (a[i][j] < 60) break; if (j < 4) { for (j = 0;j < 4;j++) printf("%d ", a[i][j]); printf("\n"); } } return 0; }
Pascal :
Program TK1277; var i,j,t:longint; a:array[0..10,0..10]of longint; Begin for i:=1 to 3 do for j:=1 to 4 do read(a[i][j]); for i:=1 to 3 do begin t:=0; for j:=1 to 4 do if a[i][j]<60 then t:=1; if t=1 then begin for j:=1 to 4 do write(a[i][j],' '); writeln; end; end; End.
Java :
import java.text.DecimalFormat; import java.util.Scanner; public class Main { private static Scanner s = new Scanner(System.in) ; private static DecimalFormat df = new DecimalFormat("0.00") ; public static void main(String[] args) { int a[][] = new int[3][4] ; int b[] = new int[3] ; for (int i = 0; i < a.length; i++) { for (int j = 0; j < a[i].length; j++) { int temp = s.nextInt(); if(temp>=0&&temp<=100) a[i][j] = temp ; } } for (int i = 0; i < a.length; i++) { for (int j = 0; j < a[i].length; j++) { if(a[i][j]<60){ b[i] = 1 ; } } } for (int i = 0; i < b.length; i++) { if(b[i]==1){ for (int j = 0; j < a[i].length; j++) { System.out.print(a[i][j]+" "); } System.out.println(); } } // double score = 0 ; // // // int n = s.nextInt() ; // for (int i = 0; i < a.length; i++) { // for (int j = 0; j < a[0].length; j++) { // score = score + a[i][j] ; // } // } // System.out.println(df.format(score/12)) ; // for (int i = 0; i < a[n].length; i++) { // System.out.print(a[n][i]+" ") ; // } } }
- 1
信息
- ID
- 1352
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者