1 条题解

  • 0
    @ 2025-4-7 21:28:48

    C :

    #include<stdio.h>
    #include<stdlib.h>
    int main()
    {
      double sum=0,ava=0;
      int n,i,j;
      int a[3][4];
      for(i=0;i<3;i++)
        for(j=0;j<4;j++)
      {
        scanf("%d",&a[i][j]);
        sum=sum+a[i][j];
      }
      scanf("%d",&n);
      ava=sum/12;
      printf("%.2lf\n",ava);
      for(i=n,j=0;j<4;j++)
        printf("%d ",a[i][j]);
      printf("\n");
    }
    

    C++ :

    #include <stdio.h>
    int main() {
    	int a[3][4];
    	int i, j, n;
    	float tot, aveg;
    	tot = 0;
    	for (i = 0;i < 3;i++)
    		for (j = 0;j < 4;j++)
    			scanf("%d", &a[i][j]);
    	scanf("%d", &n);
    	for (i = 0;i < 3;i++)
    		for (j = 0;j < 4;j++)
    			tot += a[i][j];
    	aveg = tot / (3 * 4);
    	printf("%.2f\n", aveg);
    	for (i = 0;i < 4;i++)
    		printf("%d ", a[n][i]);
    	printf("\n");
    	return 0;
    }
    
    

    Java :

    
    
    import java.text.DecimalFormat;
    import java.util.Scanner;
    
    public class Main{
       private static Scanner s = new Scanner(System.in) ;
       private static DecimalFormat df = new DecimalFormat("0.00") ;
       public static void main(String[] args) {
    	  int a[][] = new int[3][4] ;
    	  
    	  for (int i = 0; i < a.length; i++) {
    		 for (int j = 0; j < a[i].length; j++) {
    			int temp = s.nextInt();
    			if(temp>=0&&temp<=100)
    				a[i][j] = temp ;
    		}
    	  }
    	  
    	  double score = 0 ;
    	  
    	  
    	  int n = s.nextInt() ;
    	  for (int i = 0; i < a.length; i++) {
    			 for (int j = 0; j < a[0].length; j++) {
    				score = score + a[i][j] ;
    			 }
    		  }
    	  System.out.println(df.format(score/12)) ;
    	  for (int i = 0; i < a[n].length; i++) {
    		 System.out.print(a[n][i]+" ") ;
    	  }
    	  
    		  
       }
    }
    
    
    • 1

    信息

    ID
    1351
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者