1 条题解

  • 0
    @ 2025-4-7 21:28:48

    C :

    #include<stdio.h>
    #define LEAP_YEAR(y)(y)%400==0||(y)%4==0&&(y)%100!=0
    int main()
    {   
    	int year;
    	scanf("%d",&year);
    	if(year>=1000 && year<=9999)
    	{      
    		if(LEAP_YEAR(year))	  
    		{        
    			printf("%d is a leap year.\n", year);
    		}      
    		else	  
    			{      
    				printf("%d is not a leap year.\n", year);	  
    			}   
    	} 
    }
    

    C++ :

    #include <stdio.h>
    #define LEAP_YEAR(y) ((y % 4 == 0 && y % 100 != 0) || (y % 400 == 0))
    int main() {
    	int year;
    	scanf("%d", &year);
    	if (LEAP_YEAR(year))
    		printf("%d is a leap year.\n", year);
    	else
    		printf("%d is not a leap year.\n", year);
    	return 0;
    }
    
    

    Pascal :

    var
      n:longint;
    begin
      readln(n);
      if (n mod 4=0) and (n mod 100<>0) or (n mod 400=0) then writeln(n,' is a leap year.')
          else writeln(n,' is not a leap year.');
    end.
    

    Java :

    import java.util.*;
    
    public class Main{
    	public static void main (String[] args) {
    		Scanner in=new Scanner(System.in);
    		int y=in.nextInt();
    		if(y%4==0&&y%100!=0 || y%400==0)
    			System.out.println (y+" is a leap year.");
    		else
    			System.out.println (y+" is not a leap year.");
    	}
    }
    
    
    • 1

    信息

    ID
    1343
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者