1 条题解

  • 0
    @ 2025-4-7 21:28:47

    C :

    #include<stdio.h>
    int main()
    {
    	int i;
    	double max,min,sum,a[10];
    	for(i=0;i<10;i++)
    		scanf("%lf",&a[i]);
    	max=min=a[0];
    	for(sum=0,i=0;i<10;i++)
    	{
    		if(max<a[i])max=a[i];
    		if(min>a[i])min=a[i];
    		sum+=a[i];
    	}
    	printf("%.2lf %.2lf %.2lf\n",sum/10,max,min);
    	return 0;
    }
    
    

    C++ :

    #include <stdio.h>
    float max, min;
    int main() {
    	float average(float array[10]);
    	float score[10], aver;
    	int i;
    	for (i = 0;i < 10;i++)
    		scanf("%f", &score[i]);
    	aver = average(score);
    	printf("%.2f %.2f %.2f\n", aver, max, min);
    	return 0;
    }
    float average(float array[10]) {
    	int i;
    	float aver, sum = array[0];
    	max = min = array[0];
    	for(i = 1;i < 10;i++) {
    		sum = sum + array[i];
    		if (array[i] > max)
    			max = array[i];
    		if (array[i] < min)
    			min = array[i];
    	}
    	aver = sum / 10;
    	return aver;
    }
    
    

    Pascal :

    var
      s,max,min,d:double;
      i:longint;
      a:array[1..10] of double;
    begin
      for i:=1 to 10 do
      begin
      read(a[i]);
      s:=s+a[i];
      end;
      readln;
      min:=101;
      for i:=1 to 10 do
      begin
        if a[i]>max then max:=a[i];
        if a[i]<min then min:=a[i];
      end;
      d:=s/10;
      writeln(d:0:2,' ',max:0:2,' ',min:0:2);
    end.
    
    
    

    Java :

    import java.util.*;
    
    public class Main{
    	public static void main (String[] args) {
    		Scanner in=new Scanner(System.in);
    		double []a= new double [10];
    		double sum=0;
    		for(int i=0;i<10;i++){
    			a[i]=in.nextDouble();
    		}
    		for(int j=0;j<10;j++){
    			sum+=a[j];
    		}
    		System.out.printf ("%.2f ",sum/10);
    		java.util.Arrays.sort(a);
    		System.out.printf ("%.2f ",a[9]);
    		System.out.printf ("%.2f",a[0]);
    		System.out.println ();
    	}
    }
    
    
    • 1

    信息

    ID
    1319
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者