1 条题解
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0
C :
#include <stdio.h> int main(){ int n; int a[10][10]; int i,j,sum=0; scanf("%d",&n); for (i=0;i<n;i++) for (j=0;j<n;j++) scanf("%d",&a[i][j]); for (i=0;i<n;i++) sum+=a[i][i]; printf("%d\n",sum); return 0; }
C++ :
#include <stdio.h> int main() { int dat[10][10]; int n, i, j, sum; scanf("%d", &n); for (i = 0;i < n;i++) { for (j = 0;j < n;j++) { scanf("%d", &dat[i][j]); } } sum = 0; for (i = 0;i < n;i++) sum += dat[i][i]; printf("%d\n", sum); return 0; }
Pascal :
const Num=20; var a:array[1..Num,1..Num] of longint; i,j,n,sum:longint; begin readln(n); for i:=1 to n do for j:=1 to n do read(a[i,j]); sum:=0; for i:=1 to n do inc(sum,a[i,i]); writeln(sum); end.
Java :
import java.util.Scanner; public class Main { public static void main (String[] args) { Scanner in=new Scanner(System.in); int n=in.nextInt(); int [][]a=new int[n][n]; int sum=0; for(int i=0;i<n;i++) for(int j=0;j<n;j++) a[i][j]=in.nextInt(); for(int k=0;k<n;k++) sum +=a[k][k]; System.out.println (sum); } }
- 1
信息
- ID
- 1298
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者