1 条题解
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0
C :
#include<stdio.h> #include<string.h> int main(){ char a[100]; char b[100]; char c[100]; char *max; scanf("%s",a); scanf("%s",b); scanf("%s",c); max=a; if(strcmp(max,b)<0) max=b; if(strcmp(max,c)<0) max=c; printf("%s\n",max); return 0; }
C++ :
#include <stdio.h> #include <string.h> int main() { char string[101]; char str[3][101]; int i; for (i = 0;i < 3;i++) scanf("%s", str[i]); if (strcmp(str[0], str[1]) > 0) strcpy(string, str[0]); else strcpy(string, str[1]); if (strcmp(str[2], string) > 0) strcpy(string, str[2]); printf("%s\n", string); return 0; }
Pascal :
var i:longint; n,max:string; begin for i:=1 to 3 do begin readln(n); if n>max then max:=n; end; writeln(max); end.
Java :
import java.util.Arrays; import java.util.Scanner; public class Main{ private static Scanner s = new Scanner(System.in) ; public static void main(String[] args) { String strs[] = new String[3] ; for (int i = 0; i < strs.length; i++) { strs[i] = s.next() ; } Arrays.sort(strs); System.out.println(strs[strs.length-1]) ; } }
- 1
信息
- ID
- 1295
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者