1 条题解

  • 0
    @ 2025-4-7 21:28:47

    C :

    #include<stdio.h>
    int main(){
    int n,i;
      int sum=1;
      scanf("%d",&n);
      for(i=1;i<n;i++){
        sum=2*(sum+1);
      }
      printf("%d\n",sum);
      return 0;
    }
    

    C++ :

    #include <stdio.h>
    int main() {
    	int i, n, tot;
    	tot = 1;
    	scanf("%d", &n);
    	for (i = n;i > 1;i--) {
    		tot = (tot + 1) * 2;
    	}
    	printf("%d\n", tot);
    	return 0;
    }
    
    

    Pascal :

    var
      n,s,i:longint;
    begin
      readln(n);
      s:=1;
      for i:=1 to n-1 do
      s:=(s+1)*2;
      writeln(s);
    end.
    
    

    Java :

    import java.util.*;
    public class Main {
        public static void main(String args[]) {
            Scanner cin=new Scanner(System.in);
            int n=cin.nextInt();
            int[] a=new int[100];
            a[0]=1;
            for(int i=1;i<n;i++)
                a[i]=2*(a[i-1]+1);
            System.out.println(a[n-1]);
        }
    }
    

    Python :

    def peachs(n):
        if n == 1:
            ps = 1
        else :
            ps = ((peachs(n-1))+1)*2
        return ps
        
    t = int(raw_input())
    print peachs(t)
    
    
    • 1

    信息

    ID
    1283
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者