1 条题解

  • 0
    @ 2025-4-7 21:28:47

    C :

    #include<stdio.h>
    #include<math.h>
    int main(){
    int i,j;
    int m;
      for(i=100;i<=200;i++){
        m=sqrt(i);
        for(j=2;j<=m;j++)
          if(i%j==0)
            break;
        if(j>m)
          printf("%d ",i);
      }
      printf("\n");
      return 0;
    }
    

    C++ :

    #include <stdio.h>
    #include <math.h>
    int main() {
    	int i, m, prime;
    	for (m = 100;m <= 200;m++) {
    		prime = 1;
    		for (i = 2;i * i <= m;i++) {
    			if (m % i == 0) {
    				prime = 0;
    				break;
    			}
    		}
    		if (prime == 1)
    			printf("%d ", m);
    	}
    	printf("\n");
    	return 0;
    }
    
    

    Pascal :

    var
      i,j:longint;
      b:boolean;
    begin
      for i:=100 to 200 do
      begin
        b:=true;
        for j:=2 to i-1 do
        if i mod j=0 then b:=false;
        if b then write(i,' ');
      end;
    end.
    
    

    Java :

    import java.util.*;
    public class Main {
        public static void main(String args[]) {
            boolean flag;
            for(int result=100;result<=200;result++)
            {
                flag = true;
                if(result%2==0){
                    continue;
                }
                else {
                    for(int i=3;i<=Math.sqrt((double)result);i+=2){
                            if(result%i==0){
                                flag = false;
                                break;
                            }
                    }
                }
                if(flag)
                    System.out.printf("%d ",result);
            }
        }
    }
    

    Python :

    def isprime(n):
      for x in xrange(2, int(n**0.5)+1):
        if n%x == 0:
          return False
      return True
    print ' '.join(str(x) for x in xrange(100,200) if isprime(x)),''
    
    • 1

    信息

    ID
    1272
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
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