1 条题解

  • 0
    @ 2025-4-7 21:28:46

    C :

    #include<stdio.h>
    #include<math.h>
    int main()
    {
        int a,b,c,x;
    	double y,s,s1;
    	scanf("%d%d%d",&a,&b,&c);
    	x=b*b-4*a*c;
    	if(x<0)
    		printf("%s\n","no answer");
        else if(x==0)
    	{
            s=(-b)/(a*2.0);
    		printf("%.4f\n",s);
    	}
    	else
    	{
            y=sqrt(x);
    		s=(-b+y)/(2.0*a);
    		s1=(-b-y)/(2.0*a);
    		printf("%.4f %.4f\n", s1, s);
    	}
    	return 0;
    }
    

    C++ :

    #include <stdio.h>
    #include <math.h>
    int main() {
    	int a, b, c, delta;
    	double ans0, ans1, sqrt_delta;
    	scanf("%d %d %d", &a, &b, &c);
    	/* 计算delta的值(b*b-4*a*c)并分类讨论 */
    	delta = b * b - 4 * a * c;
    	if (delta > 0) {
    		sqrt_delta = sqrt(delta);
    		ans0 = (-b - sqrt_delta) / (2.0 * a);
    		ans1 = (-b + sqrt_delta) / (2.0 * a);
    		printf("%.4f %.4f\n", ans0, ans1);
    	} else if (delta == 0) {
    		ans0 = (-b) / (2.0 * a);
    		printf("%.4f\n", ans0);
    	} else {
    		printf("no answer\n");
    	}
    	return 0;
    }
    
    

    Pascal :

    var 
      a,b,c,d:double;
    
    begin
      readln(a,b,c);
      d:=b*b-4*a*c;
      if(d<0) then writeln('no answer')
        else if(d<1e-8) then writeln(-b/(2*a):0:4)
          else writeln( (-b-sqrt(d))/(2*a):0:4 ,' ', (-b+sqrt(d))/(2*a):0:4 );
    end.
    
    

    Java :

    import java.util.*;
    public class Main {
    	public static void main(String args[]) {
    		Scanner cin = new Scanner(System.in);
    		double a,b,c;
    		double d;
    		double x1,x2;
    		a=cin.nextInt();
    		b=cin.nextInt();
    		c=cin.nextInt();
    		d=Math.pow(b, 2)-4*a*c;
    		if(d==0){
    			x1=-b/(2*a);
    			System.out.printf("%.4f\n",x1);
    		}
    		else if(d>0){
    			x1=(-b+Math.sqrt(d))/(2*a);
    			x2=(-b-Math.sqrt(d))/(2*a);
    			System.out.printf("%.4f %.4f\n",x2,x1);
    		}
    		else {
    			System.out.println("no answer");
    		}
    	}
    }
    

    Python :

    from math import sqrt
    a,b,c = [float(x) for x in raw_input().split()]
    print "%.4f %.4f" %((-b-sqrt(b*b-4*a*c))/(2*a), (-b+sqrt(b*b-4*a*c))/(2*a))
    

    C# :

    using System;
    namespace C语言
    {
        class _2_9
        {
            static void Main()
            {
                string[] s = Console.ReadLine().Split(' ');
                int a = Convert.ToInt32(s[0]), b = Convert.ToInt32(s[1]), c = Convert.ToInt32(s[2]);
                if (b * b < 4 * a * c) Console.WriteLine("no answer");
                else if (b * b == 4 * a * c) Console.WriteLine("{0:f4}", -b / (2.0 * a));
                else {
                    double deta = Math.Sqrt(b * b - 4 * a * c);
                    Console.WriteLine("{0:F4} {1:F4}", (-b - deta) / (2.0 * a), (-b + deta) / (2.0 * a));
                }
             
                Console.ReadLine();        
            }
         }
    }
    
    
    • 1

    信息

    ID
    1229
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
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