1 条题解
-
0
C :
#include<stdio.h> int main(){ int n; scanf("%d",&n); if(n%3==0 && n%5==0) printf("can\n"); else printf("cannot\n"); return 0;}
C++ :
#include <stdio.h> int main() { int n; scanf("%d", &n); if (n % 3 == 0 && n % 5 == 0) printf("can\n"); else printf("cannot\n"); return 0; }
Pascal :
var n:longint; begin readln(n); if (n mod 3=0)and(n mod 5=0) then writeln('can') else writeln('cannot'); end.
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner s=new Scanner(System.in); int a=s.nextInt(); if(a%3==0&&a%5==0){ System.out.println("can"); }else System.out.println("cannot"); } }
Python :
n = input() if n%3==0 and n%5==0: print "can" else: print "cannot"
C# :
using System; namespace C语言 { class _2_9 { private static void Main() { int n=int.Parse(Console.ReadLine()); if(n%3==0&&n%5==0) Console.WriteLine("can"); else Console.WriteLine("cannot"); Console.ReadLine(); } } }
- 1
信息
- ID
- 1226
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者