1 条题解

  • 0
    @ 2025-4-7 21:28:46

    C :

    #include<stdio.h>
    int main(){
      int n;
      scanf("%d",&n);
      if(n%3==0 && n%5==0)
        printf("can\n");
      else 
        printf("cannot\n");
      return 0;}
    

    C++ :

    #include <stdio.h>
    int main() {
    	int n;
    	scanf("%d", &n);
    	if (n % 3 == 0 && n % 5 == 0)
    		printf("can\n");
    	else
    		printf("cannot\n");
    	return 0;
    }
    
    

    Pascal :

    var n:longint;
    begin
      readln(n);
      if (n mod 3=0)and(n mod 5=0) then writeln('can') else writeln('cannot');   
    end.  
    
    

    Java :

    import java.util.Scanner;
    public class Main {
     public static void main(String[] args) {
    		Scanner s=new Scanner(System.in);
    		int a=s.nextInt();
    		if(a%3==0&&a%5==0){
    			System.out.println("can");
    		}else 	System.out.println("cannot");
    
    	}
    
    }
    
    

    Python :

    n = input()
    if n%3==0 and n%5==0:
      print "can"
    else:
      print "cannot"
    

    C# :

    using System;
    namespace C语言
    {
        class _2_9
        {
            private static void Main()
            {
                int n=int.Parse(Console.ReadLine());
                if(n%3==0&&n%5==0)
                    Console.WriteLine("can");
                else Console.WriteLine("cannot");
      
                Console.ReadLine();        
            }
        }
    }
    
    
    • 1

    信息

    ID
    1226
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者