1 条题解
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0
C :
#include <stdio.h> int main() { int n,i,j,temp,p; int a[10000]; scanf("%d",&n); while( n!= 0 ) { for(i=0;i<n;i++) scanf("%d",&a[i]); for(i=1;i<n;i++) { temp = a[i]; for(j=i-1;j>=0 && temp<a[j];j--) { a[j+1]=a[j]; } a[j+1]=temp; } if(n%2 != 0) printf("%d\n",a[n/2]); else if(n%2==0) { p=(a[n/2]+a[(n/2)-1] )/2; printf("%d\n",p); } scanf("%d",&n); } return 0; }
C++ :
#include <iostream> #include <algorithm> using namespace std; int main() { int n;cin>>n; while(n!=0) { int *arr = new int[n]; for(int i=0; i<n; ++i) cin>>arr[i]; sort(arr,arr+n); int mid = n>>1; if(n&1==1) cout<<arr[mid]<<endl; else cout<<((arr[mid-1]+arr[mid])>>1)<<endl; cin>>n; } return 0; }
Pascal :
var i,j,k,l,n,m:longint; a:array[0..100000]of longint; begin readln(n); while n<>0 do begin for i:=1 to n do readln(a[i]); for i:=1 to n do for j:=1 to n do if a[i]<a[j] then begin l:=a[i];a[i]:=a[j];a[j]:=l;end; if n mod 2=1 then writeln(a[n div 2+1]); if n mod 2=0 then writeln((a[n div 2]+a[n div 2+1])div 2); readln(n); end; end.
Java :
import java.util.Arrays; import java.util.Scanner; public class Main { private static Scanner s = new Scanner (System.in) ; public static void main(String[] args) { while(true){ int N = s.nextInt() ; if(N==0){ break ; } int a[] = new int[N] ; for (int i = 0; i < N; i++) { a[i] = s.nextInt() ; } Arrays.sort(a) ; if(a.length%2==0){ System.out.println((a[a.length/2]+a[a.length/2-1])/2); }else { System.out.println(a[a.length/2]); } } } }
- 1
信息
- ID
- 1170
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者