1 条题解

  • 0
    @ 2025-4-7 21:19:28

    C :

    #include<stdio.h>
    #include<stdlib.h>
    int cul(int num)
    {
    	int count=0;
    	for(int i=num;i<=2*num;i++)
    	{
    		count+=i;
    	}
    	return count;
    }
    int main()
    {
    	int m,n;
    	int num;
    	scanf("%d",&n);
    	for(int i=1;i<=n;i++)
    	{
    		scanf("%d",&m);
    		if(m>=0)
    			num=cul(m);
    		else if(m<0)
    		{
    			printf("-");
    			num=cul(-m);
    		}
    		printf("%d\n",num);
    	}
    	//system("pause");
    	return 0;
    }
    

    C++ :

    #include <iostream>
    #include <cstdio>
    #include <cmath>
    #include <algorithm>
    using namespace std;
    
    int main()
    {
        //freopen("test.in", "r", stdin);
        //freopen("test.out", "w", stdout);
        int N, t;
        cin >> t;
        while (t--) {
            cin>>N;
            cout<<((N+2*N)*(abs(N)+1))/2<<endl;
        }
        return 0;
    }
    
    

    Pascal :

    var  n,m,i,s,j:longint;
       begin
       readln(n);
       for j:=1 to n do
        begin
         readln(m);
         s:=0;
         if m>0 then for i:=m to 2*m do   s:=s+i;
         if m<0 then for i:=2*m to m do s:=s+i;
         writeln(s);
        end;
      end.
    
    
    

    Java :

    
    
    import java.util.Scanner;
    
    public class Main {
       public static void main(String[] args) {
    	  Scanner s = new Scanner(System.in) ;
    	  
    	  int N = s.nextInt() ;
    	  
    	  for (int i = 0; i < N; i++) {
    		int n =s.nextInt() ;
    		int sum = 0 ;
    		if(n>=0){
    		for (int j = n; j <= 2*n; j++) {
    			sum = sum + j;
    		}
    	  }else {
    		  for (int j = 2*n; j <= n; j++) {
    				sum = sum + j;
    			}
    	  }
    		System.out.println(sum) ;
    	  }
      }
    }
    
    
    • 1

    信息

    ID
    1151
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者