1 条题解
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0
C :
#include <stdio.h> int main(void) { int N; int n1 = 1,n2 =2,n3,i; while(scanf("%d",&N) != EOF) { if(N == 1) { printf("%d\n",n1); } else if(N == 2) { printf("%d\n",n2); } else { n1 = 1; n2 = 2; for(i=3;i<=N;i++) { n3 = n1 + n2; n1 = n2; n2 = n3; } printf("%d\n",n3); } } return 0; }
C++ :
#include <stdio.h> int main() { int n; int a[]={1,1,2,3,5,8,13,21,34,55,89,144,233,377,610,987,1597,2584,4181,6765,10946}; scanf("%d",&n); while(n!=0) { printf("%d\n",a[n]); n=0; scanf("%d",&n); } return 0; }
Pascal :
var i,n:longint; a,b,c:qword; begin while not eof do begin readln(n); a:=1;b:=2; for i:=3 to n do begin c:=a+b; a:=b; b:=c; end; if n=1 then writeln(1); if n=2 then writeln(2); if n>=3 then writeln(c); end; end.
Java :
import java.io.PrintStream; import java.util.Scanner; public class Main { static int add(int n) { if(n==1||n==2) return n; else return add(n-1)+add(n-2); } public static void main(String[] args ) { int n,sum; Scanner sc = new Scanner(System.in); PrintStream ps = new PrintStream(System.out); while(sc.hasNext()) { n= sc.nextInt(); sum=add(n); ps.printf("%d\n",sum); } } }
- 1
信息
- ID
- 1107
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者