1 条题解

  • 0
    @ 2025-2-21 20:02:37

    C :

    #include<stdio.h>
    #include<math.h>
     int main()
    {   
    	 int i,k,m,T;   
    	 scanf("%d",&T);
    	 while(T--)
    	 {
    		
    	 scanf("%d",&i);  
    	 if(i<=1) printf("NO\n",i);
    	 else
    	 {
    			 k=sqrt(i);
    		  for(m=2;m<=k;m++)    
    			if(i%m==0)break;     
    			  if(m>k)    
    				  printf("YES\n",i);   
    			  else  
    				  printf("NO\n",i);
    			  }
    	 }
    	  return 0;
     }
    
    

    C++ :

    #include<stdio.h>
    int main()
    {
        int i,j,k;
        int t,n,m;
        scanf("%d",&t);
        while(t--)
        {
            int flag=1;
            scanf("%d",&n);
            if(n<=1)
            {
                printf("NO\n");
                continue;
            }
            for(i=2;i*i<=n;i++)
            {
                if(n%i==0)
                {
                    flag=0;
                    break;
                }
            }
            if(flag)
                printf("YES\n");
            else
                printf("NO\n");
        }
        return 0;
    }
    
    

    Java :

    import java.util.Scanner;
    public class Main{
    public static boolean isPrime(int num) {
    	if(num==0||num==1){
    		num=4;
    	}
      boolean prime = true;
      int limit = (int) Math.sqrt(num);
      for (int i = 2; i <= limit; i++) {
    	  if (num % i == 0) {
        prime = false;
        break;
       }
      }
      return prime;
    }
    public static void main(String[] args) {
      Scanner input = new Scanner(System.in);
      int T = input.nextInt();
      for(int i=0;i<T;i++){
      int n = input.nextInt();
      if (isPrime(n)) {
       System.out.println("YES");
      } else {
       System.out.println("NO");
      }
    }
    }
    }
    
    
    • 1

    信息

    ID
    1005
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者